It’s not difficult, just always having some doubts…

#### Power

$latex L_{dB} = 10 log_{10} ( ) $

10 dB increase for a factor 10 increase in the ratio

3 dB = doubling

40 dB = 10000 times

#### Amplitude

$latex L_{dB} = 10 log_{10} ( ) = 20 log_{10} ( ) $

#### dBm

dBm is an absolute value obtained by a ratio with 1 mW:

$latex L_{dBm} = 10 log_{10} ( ) $

- 0 dBm = 1 mW
- 3 dBm ≈ 2 mW